Asked by Hannah
A sample of chlorine gas at a pressure of 420 mm Hg and in a volume of 3.50L was heated from 18.0 degrees celsius to 45 degrees celsius after being transferred to a container of volume 2.35L. The pressure in this new container should be about?
Would I use (p1)(v1) = (p2)(v2)
420 * 3.50 = 2.35* v2
Would I use (p1)(v1) = (p2)(v2)
420 * 3.50 = 2.35* v2
Answers
Answered by
DrBob222
The problem is confusing. What is the original T when P is 420 mm Hg and in the 3.50L container? If it is 18 C, then use
(P1V1/T1) = (P2V2/T2). If it isn't 18 C, then I don't know what the problem is asking.
(P1V1/T1) = (P2V2/T2). If it isn't 18 C, then I don't know what the problem is asking.
Answered by
Hannah
Yes the original T is 18 degrees celsius so would it be
420*3.50 / 291 K = p2 * 2.35 / 318
5.05 = p2 * 2.35 / 318.
I am just not sure how to solve for the right side of the equation to find p2.
420*3.50 / 291 K = p2 * 2.35 / 318
5.05 = p2 * 2.35 / 318.
I am just not sure how to solve for the right side of the equation to find p2.
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