Asked by L
                A sample of chlorine gas (Cl2) occupies 180 mL at -5°C. This gas doubles in volume (with no changes in pressure or amount). What is the new temperature in degrees Celsius?
            
            
        Answers
                    Answered by
            DrBob222
            
    V1 = 180 mL
V2 = doubled; i.e. 2*180 = 360 mL
T1 = -5 C or 273 - 5 = ? K
T2 = ? in Kelvin.
Use = (V1/T1) = (V2/T2) and solve for T2 ( in Kelvin).
Convert K to C by K = 273 + C and solve for C.
Post your work if you get stuck.
    
V2 = doubled; i.e. 2*180 = 360 mL
T1 = -5 C or 273 - 5 = ? K
T2 = ? in Kelvin.
Use = (V1/T1) = (V2/T2) and solve for T2 ( in Kelvin).
Convert K to C by K = 273 + C and solve for C.
Post your work if you get stuck.
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