Asked by L
A sample of chlorine gas (Cl2) occupies 180 mL at -5°C. This gas doubles in volume (with no changes in pressure or amount). What is the new temperature in degrees Celsius?
Answers
Answered by
DrBob222
V1 = 180 mL
V2 = doubled; i.e. 2*180 = 360 mL
T1 = -5 C or 273 - 5 = ? K
T2 = ? in Kelvin.
Use = (V1/T1) = (V2/T2) and solve for T2 ( in Kelvin).
Convert K to C by K = 273 + C and solve for C.
Post your work if you get stuck.
V2 = doubled; i.e. 2*180 = 360 mL
T1 = -5 C or 273 - 5 = ? K
T2 = ? in Kelvin.
Use = (V1/T1) = (V2/T2) and solve for T2 ( in Kelvin).
Convert K to C by K = 273 + C and solve for C.
Post your work if you get stuck.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.