Asked by Gary

4.80 dm^3 of chlorine gas was reacted with NaOH solution.
a) how many moles of Cl2 reacted
b) what mass of NaOCl was formed?
c) if the concentration of the NaOH was 2.00 mol/dm^3. What volume of sodium hydroxide solution was required?

d) write an ionic equation for this reaction
Answered by DrBob222
a. Actually, no one knows; however, if all 4.80 dm^3 reacted AND the Cl2 gas was at STP, then it is 4.80/22.4 = ?

b. Can't answer b,c,d. Is NaOH concd or dilute? Is it hot or cold?
Here are a couple of reactions but there are others.
2 NaOH (conc., cold) + Cl2 = NaClO + NaCl + H2O

6 NaOH (conc.,hot) + 3Cl2 = NaClO3 + 5NaCl + 3H2O.
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