Question
whats the exponential decay equation for 100 atoms that decay 1/20 per day
Answers
Damon
1/20 = .05
dn/dt = -.05 n
dn/n = -.05 dt
ln n = -.05 t + c
n = C e^-.05 t
n = 100 e^-.05 t
dn/dt = -.05 n
dn/n = -.05 dt
ln n = -.05 t + c
n = C e^-.05 t
n = 100 e^-.05 t
Steve
Hmm. Since the amount present on day n is 0.95 times the amount on day (n-1) I think the equation should be
n = 100*0.95<sup>t</sup>
= 100 * e<sup>ln.95 t</sup>
ln.95 = -.05129
I keep thinking this is absorbed into the c of the integral, but that must certainly be 100.
How to reconcile?
n = 100*0.95<sup>t</sup>
= 100 * e<sup>ln.95 t</sup>
ln.95 = -.05129
I keep thinking this is absorbed into the c of the integral, but that must certainly be 100.
How to reconcile?