Asked by Beth
A first order exponential decay can be written as
A(t)= Ae^(-t/r)
where A(t) is the amount (of substance) after time t, A is the initial amount at time t=0 and r is the decay time.
The fall time is defined as the time in which A(t) falls from 90% to 10% of its initial value. Find the relationship between the fall time of an exponential decay and r.
A(t)= Ae^(-t/r)
where A(t) is the amount (of substance) after time t, A is the initial amount at time t=0 and r is the decay time.
The fall time is defined as the time in which A(t) falls from 90% to 10% of its initial value. Find the relationship between the fall time of an exponential decay and r.
Answers
Answered by
bobpursley
I will start it off
.9=e^t1/r
ln .9 = t1/r
likewise..
ln .1=t2/r
tfall=t2-t1, well you do that...
.9=e^t1/r
ln .9 = t1/r
likewise..
ln .1=t2/r
tfall=t2-t1, well you do that...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.