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Consider a marble moving on a horizontal track with a speed of 10 meters per second( ignore friction and air resistance). the marble leaves the track and falls through the air to the ground a vertical distance of 1.5 meters.
how long does it take to for the marble to hit the ground?
13 years ago

Answers

Henry
d = Vo*t + 0.5g*t^2 = 1.5 m.
0 + 4.9*t^2 = 1,5,
t^2 = 0.306,
t = 0.553 s.
13 years ago

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