Ask a New Question

Asked by Anonymous

FIND THE AREA OF THE REGION BOUNDED BY THE CURVES Y= X^2 + 4X + 3 AND Y= x-1.
13 years ago

Answers

Answered by Reiny
There is no area.
The two graphs do not intersect , so you have no closed region.
13 years ago
There are no AI answers yet. The ability to request AI answers is coming soon!

Submit Your Answer


We prioritize human answers over AI answers.

If you are human, and you can answer this question, please submit your answer.

Related Questions

a) Find the area of the region R bounded by the graphs of the equations y=2x−x^2, x=0, and y=0. b... find the area of the region bounded by the graphs of y=x^2 and y=cos(x) Find the area of the region between a regular hexagon with sides of 6" and its inscribed circle. Find the area of the region that lies inside the first curve and outside the second curve. r = 1 +... Find the area of the region enclosed by the inner loop of the curve. r = 4 + 8 sin(θ) Find the area of the region bounded by the graphs of y = −x2 + 3x + 4 and y = 4. a) 2.7 b) 4.5... find the area of the region bounded by y=1-2x^2 and y=|x| Find the area of the region that is inside the graph of r = 1 and outside of the graph of r = 1 + co... Find the area of the region bounded by the curve r=sinθ+cosθand lies in the sector 0≤θ≤π
Submit Your Answer

Question

FIND THE AREA OF THE REGION BOUNDED BY THE CURVES Y= X^2 + 4X + 3 AND Y= x-1.

Ask a New Question
Archives Contact Us Privacy Policy Terms of Use