Asked by Beatrice
The perimeter of an isosceles triangle is 16 in. The area of the triangle is 12 sq in. If the base is x in, the height is 4 in and the legs are y in, find the length of the three sides.
Answers
Answered by
Anonymous
A = x * h / 2 = 16 in ^ 2
16 = x * 4 / 2 Multiply both sides with 2
32 = 4 x Divide both sides with 4
8 = x
x = 8 in
P = x + 2 y = 16
16 = 8 + 2 y
16 - 8 = 2 y
8 = 2 y Divide both sides with 2
8 / 2 = y
4 = y
y = 4 in
16 = x * 4 / 2 Multiply both sides with 2
32 = 4 x Divide both sides with 4
8 = x
x = 8 in
P = x + 2 y = 16
16 = 8 + 2 y
16 - 8 = 2 y
8 = 2 y Divide both sides with 2
8 / 2 = y
4 = y
y = 4 in
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.