Question

a bowling ball of mass 6.5 kg rolled with a velocity of 12m/s. The ball hits a 1.3kg bowling pin. Sending it off with a speed of 3.5m/s at an angle of 80 degrees with respect to the original direction of the bowling ball whats is the angle and direction of the bowling balls velocity after the collision with the pin?

Answer 1

final momentum vector = original momentum vector

original:
x direction: 6.5 * 12
y direction: 0

Final:
x direction: 6.5*v cos A + 1.3*3.5 cos 80
y direction: 6.5*v sin A - 1.3*3.5 sin 80

Answer 2

3.3