Asked by Amarah

a bowling ball of mass 7.00 kg moves east with a speed of 2.00 m/s. the ball collides with an identical ball at rest, which causes the first ball to move 30.0 degree north of east at a speed of 1.73 m/s. what is the velocity of the second ball after the collision?
Answered by oobleck
since the masses are the same, conserving momentum just means conserving velocities, so
2.00i = 1.5i + 0.865j + v
so v = 0.5i - 0.865j = 1.00 m/s @ -60°