Asked by kristine

A bowling ball of mass 9 kg hits a wall going 11 m/s and rebounds at a speed of 8 m/s. What was the impulse applied to the bowling ball?

Answers

Answered by Damon
impulse = change in momentum
= 9*11 + 9*8
kg m/s
Answered by Natalie
172 or 171 just took the test
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