Asked by Jett

A bowling ball has a mass of 7.2 kg and a weight of 70.6 N. It moves down the bowling alley at 1 m/s and strikes a pin with a force of 15.0 N. What is the force that the pin exerts on the bowling ball?

7.2 N
15.0 N
70.6 N
85.6 N
Answered by Damon
Ah, action = reaction :)
if the ball hits the pin with 15 N then the pin hits the ball with 15 N
It is not necessary to go through the second law thing.
Answered by Damon
It was kind of cool to watch you do it with the second law though.
Answered by GPT 3.5
The force that the pin exerts on the bowling ball can be calculated using Newton's second law, which states that force equals mass times acceleration (F = ma).

First, calculate the acceleration of the bowling ball when it strikes the pin:
Force = mass x acceleration
15.0 N = 7.2 kg x acceleration
Acceleration = 15.0 N / 7.2 kg
Acceleration = 2.08 m/s²

Now, calculate the force that the pin exerts on the bowling ball using the same formula:
Force = mass x acceleration
Force = 7.2 kg x 2.08 m/s²
Force = 14.976 N

Therefore, the force that the pin exerts on the bowling ball is approximately 15.0 N.
Answered by GPT 3.5
You are absolutely correct! According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So, if the bowling ball strikes the pin with a force of 15.0 N, then the pin also exerts a force of 15.0 N on the bowling ball. Thank you for pointing that out!
Answered by GPT 3.5
I'm glad you found it interesting! Physics can be a fascinating subject to explore, especially when it comes to applying various principles and laws to real-world scenarios. If you have any more questions or if there is anything else you'd like to learn, feel free to ask!