Asked by yo

(sinx)^2+cosx +1 = 0 , domain: [0,2pi)

aydame por favor




gracias
Answered by Steve
1 - (cosx)^2 + cosx + 1 = 0
cos^2 - cos - 2 = 0
(cosx - 2)(cosx + 1) = 0

cosx no puede ser 2

cosx = -1

x = pi
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