Asked by Anonymous
An electric motor develops 73 kW of power as it lifts a loaded elevator 20.0 m in 35 s. How much force does the motor exert?
Answers
Answered by
Henry
P = FV,
F = P/V = (73,000) / (20 m / 35s) = 127,750 N.
F = P/V = (73,000) / (20 m / 35s) = 127,750 N.
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