Question
An electric motor is rated to have a maximum power output of 0.72 hp. If this motor is being used to lift a crate of mass 188 kg, how fast (i.e., at what speed) can it lift the crate? Hint: Assume the only other force on the crate is the force of gravity.
Answers
0.72 hp =536.9 W
P = m•g•v
v =P/mg = 536.9/188•9.8 =0.29 m/s.
P = m•g•v
v =P/mg = 536.9/188•9.8 =0.29 m/s.
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