Asked by Lindsey
Find all the solutions of the following triangle using the Law of Sines.
Angle A: 83°20'
Angle C: 54.6°
c: 18.1
How would I find I find angle B? I know that you would subtract angle A and C from 180, but I do not understand how to maintain the minutes (') on my calculator.
Angle A: 83°20'
Angle C: 54.6°
c: 18.1
How would I find I find angle B? I know that you would subtract angle A and C from 180, but I do not understand how to maintain the minutes (') on my calculator.
Answers
Answered by
Steve
You could always punch in
1/3 + 83 sin
to get sin of 83 1/3 degrees.
Or, just get sin 83.333333333 degrees. It should be close enough.
So, assuming you can in fact evaluate your sines, just use the fact that
A+B+C = 180°
so, B = 180° - 83°20' - 54°36' = 42°4' = 42 1/15 ° = 42.06666666°
b/sinB = c/sinC
b = csinB/sinC = 18.1(.67)/.815 = 14.88
1/3 + 83 sin
to get sin of 83 1/3 degrees.
Or, just get sin 83.333333333 degrees. It should be close enough.
So, assuming you can in fact evaluate your sines, just use the fact that
A+B+C = 180°
so, B = 180° - 83°20' - 54°36' = 42°4' = 42 1/15 ° = 42.06666666°
b/sinB = c/sinC
b = csinB/sinC = 18.1(.67)/.815 = 14.88
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