Asked by Anonymous
Find all the solutions of 2 sinx=1-cosx in the interval from 0° ≤x<360°
Answers
Answered by
Steve
4 sin^2 = 1 - 2cos + cos^2
4 - 4 cos^2 = 1 - 2cos + cos^2
5cos^2 - 2cos - 3 = 0
cosx = 1 or -.6
x = 0 or 126.86°
4 - 4 cos^2 = 1 - 2cos + cos^2
5cos^2 - 2cos - 3 = 0
cosx = 1 or -.6
x = 0 or 126.86°
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