Asked by Grace
How do I find all solutions in the interval [0, 2Pi):
cotx=cscx-1
the answer choices are:
a.) x=Pi/2
b.) x=Pi/2 and 3Pi/2
cotx=cscx-1
the answer choices are:
a.) x=Pi/2
b.) x=Pi/2 and 3Pi/2
Answers
Answered by
Reiny
pi/2 surely works, (try subbing it in)
remember that 3pi/2 is 270º
tan 270º is undefined, so cot 270º = 0
LS = cot 3pi/2 = 0
RS = 1/sin 270 - 1 = 1/-1 - 1 = -2
so 3pi/2 does not work.
remember that 3pi/2 is 270º
tan 270º is undefined, so cot 270º = 0
LS = cot 3pi/2 = 0
RS = 1/sin 270 - 1 = 1/-1 - 1 = -2
so 3pi/2 does not work.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.