A soccer ball of mass 450 grams is initially moving horizontally east at 12 m/s. You kick it so that it moves horizontally north at 13 m/s. The collision lasts 0.04 s. Find the magnitude and direction of the average force you apply to the ball.

Question

|F| =

Angle from East =

Answer 1

Divide the momentum change vector by 0.04 s.

The magnitude of the momentum change vector is
sqrt[(12)^2 + (13^2] = 17.69 N*s
Next, do the division.

The direction is the direction of the momentum change.
arctan13/12 = 47.3 degrees from east

Answer 2

not right