Asked by Tsun

A .25 kg soccer ball is rolling at 6 m/s toward a player. The player kicks the ball back in the opposite direction and gives it a speed of 14 m/s. The interaction only lasted .02 seconds. Calculate the average force during the interaction.

Calculate the magnitude of the average acceleration of the soccer ball while it's being kicked.

a. 62.5 ms^2
b. 100 ms^2
c. 400 ms^2
d. 1000 ms^2

Answers

Answered by Damon
change in momentum / 0.02
Answered by Damon
.25(6+14) = 5
5/.02 = 500/2 = 250 N
a = F/m = 250 N/.25 = 1000 m/s^2
I get d.
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