Question

A .22 rifle bullet traveling at 360m/s strikes a block of wood, which penetrates to a depth of .110m. The mass of the bullet is 1.80g. Assume a constant retarding force.A) how much time is required for the bullet to stop? b) what force in newtons soes the wood exert on the bullet?

a) should have been 6.11X10^-4 s
b) should have been 1060N
For a) I tried using v=d/t for time and for b) I used f=ma to find the force. What am I doing incorrectly?

The average force on the wood * distance= KE of the bullet

F*.11= 1/2 .0018*360^2

That will give you the average force.

time? avgvelocity*time= distance
1/2 360 * time= .110
Time= you do it.

Hi Bob
Care to elaborate on that clock question that I left you a note on below? I don't get it. I'm dying with curosity.
You can get the answer of time by having this formula :

x = 1/2 (v0-v)a.t

just transpose it. . . . .

a= 9.806 m/s^2

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