Asked by Chris
A .22 rifle bullet traveling at 360m/s strikes a block of wood, which penetrates to a depth of .110m. The mass of the bullet is 1.80g. Assume a constant retarding force.A) how much time is required for the bullet to stop? b) what force in newtons soes the wood exert on the bullet?
a) should have been 6.11X10^-4 s
b) should have been 1060N
For a) I tried using v=d/t for time and for b) I used f=ma to find the force. What am I doing incorrectly?
The average force on the wood * distance= KE of the bullet
F*.11= 1/2 .0018*360^2
That will give you the average force.
time? avgvelocity*time= distance
1/2 360 * time= .110
Time= you do it.
Hi Bob
Care to elaborate on that clock question that I left you a note on below? I don't get it. I'm dying with curosity.
a) should have been 6.11X10^-4 s
b) should have been 1060N
For a) I tried using v=d/t for time and for b) I used f=ma to find the force. What am I doing incorrectly?
The average force on the wood * distance= KE of the bullet
F*.11= 1/2 .0018*360^2
That will give you the average force.
time? avgvelocity*time= distance
1/2 360 * time= .110
Time= you do it.
Hi Bob
Care to elaborate on that clock question that I left you a note on below? I don't get it. I'm dying with curosity.
Answers
Answered by
Quinee
You can get the answer of time by having this formula :
x = 1/2 (v0-v)a.t
just transpose it. . . . .
a= 9.806 m/s^2
x = 1/2 (v0-v)a.t
just transpose it. . . . .
a= 9.806 m/s^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.