Question

A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (uniform acceleration)

Answer 1

V^2 = 2ad = (521)^2,
2a*0.84 = 271441,
168a = 271441,
a = 271441 / 1.68 = 161572 m/s^2.

Answer 2

Thanks but on topper website it is solved in another way which seems correct. I want to understand that way....Could you explain?

Answer 3

Henry just used the equation V2² = V1² + 2ad where V1 (Initial velocity) is 0. Therefore it is shortened to:
V2² = 2ad
V2² / (2d) = a