Asked by devin
If the radiicativr decay of nuclear explosion contains 90 Sr , with a half life of 28.1 years how long will it take for 99 of this radioaioot to decay
Answers
Answered by
DrBob222
99 what? 99 grams? 99 tons? 99%. I suspect 99%.
Two steps. First determine k.
k = 0.693/t<sub>1/2</sub> and substitute into the following:
ln(No/N) = kt
I would set No = 100 if that is 99%.
Then N = 1% (if 99% is gone)
k from above
Solve for t in years.
Two steps. First determine k.
k = 0.693/t<sub>1/2</sub> and substitute into the following:
ln(No/N) = kt
I would set No = 100 if that is 99%.
Then N = 1% (if 99% is gone)
k from above
Solve for t in years.
Answered by
devin
Sorry don't understand it is 99 percent
Answered by
devin
Ln(100)/1)=(0.693/t^1/2)(t). ??? Don't get it
Answered by
DrBob222
There isn't anything to get. Can you punch the calculator? That's all there is to it. Do it in steps. Don't try to muddle it up by putting all of it together.
ln 100/1 = 4.605
0.693/28.1 = 0.02466 = k
so
ln(100/1) = 0.02466*t
4.605 = 0.02466t
and t = 4.605/0.02466 = ? or about 200 years more or less.
ln 100/1 = 4.605
0.693/28.1 = 0.02466 = k
so
ln(100/1) = 0.02466*t
4.605 = 0.02466t
and t = 4.605/0.02466 = ? or about 200 years more or less.