Ask a New Question

Asked by Anonymous

The decay of 200 particles of a particular radioactive substance is given by y=200(0.93)^x, where x is the number of days and y is the number of particles remaining. It costs the laboratory $1.50 per day to store each particle. On which day will the cost to store the particles be $135.

a) day 4
b) day 11
c) day 9
d) day 5
4 years ago

Answers

Answered by Anonymous
y = 135/1.50 = 90 particles
90 = 200 * .93^x
0.45 = .93^x
log 0.45 = x log 0.93
-.347 = x * -.0315
x = 11
4 years ago
Answered by Anonymous
Lo and behold, 11 is an answer choice.
4 years ago

Related Questions

If the radiicativr decay of nuclear explosion contains 90 Sr , with a half life of 28.1 years how lo... The table below the C-14 Decay curve and the Correction curves contains the % Modern values for 4 sa... This is Growth and Decay 1. The U.S. populace increases at 0.91% per year. If the population in... What is the decay factor of 50% spending cut? In a lab experiment, the decay of a radioactive isotope is being observed. At the beginning of the f... Is y=5(2)^x a growth or decay? What is the decay constant of 11Be in units of 1/S? define alpha decay, gamma decay, beta decay use short sentences then make a super extremely small s... What is the decay rate? y = 75 * (0.96) ^ t Group of answer choices 96% 95% 5% 4% How is radioactive decay used to date sedimentary rocks? The amounts of potassium and argon in se...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use