Ask a New Question

Question

A 48 g ball is released from rest at h = 1.4 m above the bottom of the track shown in the figure below. It rolls down a straight 30° segment, then back up a parabolic segment whose shape is given by y = 1/4 x2, where x and y are in m. How high will the ball go on the right before reversing direction and rolling back down? Neglect friction.
13 years ago

Answers

Related Questions

A 50 g ball is released from rest 1.0 m above the bottom of the track shown in the figure. It rolls... A bowling ball is released at the near right corner of a bowling lane and travels 19.1 m at an angle... if a ball is released from a certain height.The velocity-time graph which represents the motion of... If the ball is released from rest at a height of 0.64 m above the bottom of the track on the no-slip... a 0.20 kg ball is released from a height of 10 m above the beach; the impression the ball makes in t... A ball is released from a hot air balloon moving downward with a velocity of -10.0 meters/second an... a ball is released from the top of a 67.0 m high building. At the same instant a second ball is shot... A ball is released at a height of h=3.00 m on a frictionless 30.0 degree slope. At the bottom, it tu... The tennis ball was released from a shooting pot with the initial velocity of 30m/s at the angle o... A ball Is released at a height of 8 inches to roll inside a half-cylinder. It rolls to a height of 2...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use