Question

in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x-11 what proves ABCD a rhombus

Answer 1

It's a rhombus if the diagonal bisects the angles. So, if

2x+4 = 5x-11

the ABCD is a rhombus

Answer 2

^^^ is correct

Answer 3

indeed

Answer 4

how do you work out x ?

Answer 5

A decade later we still looking for the right answer lol