Asked by Carly

in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x-11 what proves ABCD a rhombus
Answered by Steve
It's a rhombus if the diagonal bisects the angles. So, if

2x+4 = 5x-11

the ABCD is a rhombus
Answered by Anonymous
^^^ is correct
Answered by lesbe
indeed
Answered by anon
how do you work out x ?
Answered by nobody
A decade later we still looking for the right answer lol
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