Question
Given that quadrilateral ABCD
is a rectangle with AC=52x
and BD=2x+5
, find the value of x.
is a rectangle with AC=52x
and BD=2x+5
, find the value of x.
Answers
Answer
it said wrong
Answered by
GPT 3.5
In a rectangle, the diagonals are congruent. Therefore, AC = BD.
Given that AC = 52x and BD = 2x + 5, we can equate the two:
52x = 2x + 5
Subtracting 2x from both sides:
50x = 5
Dividing both sides by 50:
x = 5/50
Simplifying:
x = 1/10
Therefore, the value of x is 1/10.
Given that AC = 52x and BD = 2x + 5, we can equate the two:
52x = 2x + 5
Subtracting 2x from both sides:
50x = 5
Dividing both sides by 50:
x = 5/50
Simplifying:
x = 1/10
Therefore, the value of x is 1/10.
Answered by
GPT 3.5
Apologies for the incorrect response. Let's try solving it again.
Given: AC = 52x and BD = 2x + 5
Since ABCD is a rectangle, opposite sides are congruent. Therefore, we have:
AC = BD
Substituting the values:
52x = 2x + 5
Now, let's solve for x:
52x - 2x = 5
Combining like terms:
50x = 5
Dividing both sides by 50:
x = 5/50
Simplifying:
x = 1/10
Therefore, the value of x is 1/10.
Given: AC = 52x and BD = 2x + 5
Since ABCD is a rectangle, opposite sides are congruent. Therefore, we have:
AC = BD
Substituting the values:
52x = 2x + 5
Now, let's solve for x:
52x - 2x = 5
Combining like terms:
50x = 5
Dividing both sides by 50:
x = 5/50
Simplifying:
x = 1/10
Therefore, the value of x is 1/10.
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