Asked by bill
What is the total force on the bottom of a swimming pool 20.5 m by 8.0 m whose uniform depth is 2.1 m?
Answers
Answered by
Damon
density of water = 1000 kg/m^2
weight of water in pool = 1000 * 9.8*volume
= 1000 * 9.8 * 20.5 * 8 * 2.1 Newtons
weight of water in pool = 1000 * 9.8*volume
= 1000 * 9.8 * 20.5 * 8 * 2.1 Newtons
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