Asked by Blessong
the total force opposing motion of the box and the parachute at particular time during its fall is 30N.the combined mass of the box and parachute is 5kg
1. Caculate the resultant downward force and box and the parachute (g=10N)
1. Caculate the resultant downward force and box and the parachute (g=10N)
Answers
Answered by
Damon
mg downward
30 N upward
net downward = m g - 30
g is not in Newtons but in m/s^2.
It is more like 9.81 m/s^2 on earth but ok, use 10 m/s^2
net downward = 5 kg ( 10 m/s^2) - 30
= 50 - 30
= 20 Newtons
30 N upward
net downward = m g - 30
g is not in Newtons but in m/s^2.
It is more like 9.81 m/s^2 on earth but ok, use 10 m/s^2
net downward = 5 kg ( 10 m/s^2) - 30
= 50 - 30
= 20 Newtons
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