Asked by Dwayne
I lost the last link....
Triangle DEF has D= 58 degrees, E= 41degrees52', and f(little f)= 0.032 microns. Find d
52/60 (to get the inches gone)
58+41.86(repeating for quite a fe2 digits)
180-99.86666667=80.13333
So my equation is f Sin85/Sin80.1333
How does the microns impact in? I've don't remember microns and that is what is throwing me.
Triangle DEF has D= 58 degrees, E= 41degrees52', and f(little f)= 0.032 microns. Find d
52/60 (to get the inches gone)
58+41.86(repeating for quite a fe2 digits)
180-99.86666667=80.13333
So my equation is f Sin85/Sin80.1333
How does the microns impact in? I've don't remember microns and that is what is throwing me.
Answers
Answered by
Reiny
First of all in 41° 52' the 52' does not refer to "inches", but rather to "minutes" where 60 minutes = 1 degree
so angle E = 41 13/15°
and angle F = 80 2/15°
f = .032 refers to the magnitude of side f or side ED
microns are just units of length, so that 1 "mircron" = 1.0 x 10^-6 m
So use the sine law to find the other two sides.
To find e or DF
e/sin E = .032/sin F
e = .032sinE/sinF
e = 0.32(.667399..)/.9852..)
e = .021677 or e = .022
(to get sin 41° 52', I typed
sin
(41 + 52÷60)
=
to get .667399419)
I will let you find the other side in the same way.
so angle E = 41 13/15°
and angle F = 80 2/15°
f = .032 refers to the magnitude of side f or side ED
microns are just units of length, so that 1 "mircron" = 1.0 x 10^-6 m
So use the sine law to find the other two sides.
To find e or DF
e/sin E = .032/sin F
e = .032sinE/sinF
e = 0.32(.667399..)/.9852..)
e = .021677 or e = .022
(to get sin 41° 52', I typed
sin
(41 + 52÷60)
=
to get .667399419)
I will let you find the other side in the same way.
Answered by
Dwayne
I think I figured it out...
0.032sin58/.9852
0.2754
0.032sin58/.9852
0.2754
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