Asked by Kaleen
Calculate the pH of a 0.053 M (C2H5)2NH solution (Kb = 1.3 10-3).
Answers
Answered by
DrBob222
..........B2NH + HOH ==> B2NH2^+ + OH^-
initial....0.053..........0.........0
change....-x..............x.........x
equil.....0.053-x.........x..........x
Kb = (B2NH^+)(OH^-)/(B2BH)
Substitute into Kb expression and solve for x (which is OH^-). Convert to pH.
initial....0.053..........0.........0
change....-x..............x.........x
equil.....0.053-x.........x..........x
Kb = (B2NH^+)(OH^-)/(B2BH)
Substitute into Kb expression and solve for x (which is OH^-). Convert to pH.
Answered by
Autumn
2.13
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.