Question
a person throws a ball upward into the air with an initial velocity of 15 m/s calculate
a)how high it goes?
b)how long the ball is in the air before it comes back ?
c)how much time it takes for the ball to reach the maximum height?
a)how high it goes?
b)how long the ball is in the air before it comes back ?
c)how much time it takes for the ball to reach the maximum height?
Answers
Steve
h = 15t - 4.9t^2 = 4.9t(3.06-t)
(c) max height is reached at t = 15/9.8
(b) h=0 when t=0 or 3.06
(a) calculate h using (a)
(c) max height is reached at t = 15/9.8
(b) h=0 when t=0 or 3.06
(a) calculate h using (a)