Asked by nour
a person throws a ball upward into the air with an initial velocity of 15 m/s calculate
a)how high it goes?
b)how long the ball is in the air before it comes back ?
c)how much time it takes for the ball to reach the maximum height?
a)how high it goes?
b)how long the ball is in the air before it comes back ?
c)how much time it takes for the ball to reach the maximum height?
Answers
Answered by
Steve
h = 15t - 4.9t^2 = 4.9t(3.06-t)
(c) max height is reached at t = 15/9.8
(b) h=0 when t=0 or 3.06
(a) calculate h using (a)
(c) max height is reached at t = 15/9.8
(b) h=0 when t=0 or 3.06
(a) calculate h using (a)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.