Question
a person throws a ball upward into the air with an initial velocity of 20.0 m/s, calculate how high it goes
Answers
drwls
It rises to height H such that the potential energy gain equals initial kinetic energy.
M g H = (1/2) M V^2
H = V^2/(2 g)
M g H = (1/2) M V^2
H = V^2/(2 g)