Asked by Haze
A student throws a ball upward from a height of 48ft, initially at 32ft per second. What is the maximum height of the ball?
Answers
Answered by
Reiny
your function for the height is
h = -16t^2 + 32t + 48
find the vertex of this quadratic function using whatever method you have learned.
Since you titled your post "Calculus",
find the derivative, set it equal to zero and solve for t.
Finally, plug that t value back into my function.
h = -16t^2 + 32t + 48
find the vertex of this quadratic function using whatever method you have learned.
Since you titled your post "Calculus",
find the derivative, set it equal to zero and solve for t.
Finally, plug that t value back into my function.
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