Asked by brianna
log4(little 4) 8
how do i write this in y=?
how do i write this in y=?
Answers
Answered by
MathMate
Use the laws of logarithms,
log ab = log a+log b
log<sub>a</sub>a = 1, and
log<sub>a</sub> sqrt(b)=(1/2)log<sub>a</sub> b
log 8
= log<sub>4</sub>4*2
=log<sub>4</sub>4+log<sub>4</sub>2
=1+log<sub>a</sub>2
=1+(1/2)log<sub>4</sub>2
=1+(1/2)(1)
=3/2
log ab = log a+log b
log<sub>a</sub>a = 1, and
log<sub>a</sub> sqrt(b)=(1/2)log<sub>a</sub> b
log 8
= log<sub>4</sub>4*2
=log<sub>4</sub>4+log<sub>4</sub>2
=1+log<sub>a</sub>2
=1+(1/2)log<sub>4</sub>2
=1+(1/2)(1)
=3/2
Answered by
MathMate
Use the laws of logarithms,
log ab = log a+log b
log<sub>a</sub>a = 1, and
log<sub>a</sub> sqrt(b)=(1/2)log<sub>a</sub> b
log 8
= log<sub>4</sub>4*2
=log<sub>4</sub>4+log<sub>4</sub>2
=1+log<sub>4</sub>2
=1+(1/2)log<sub>4</sub>4
=1+(1/2)(1)
=3/2
log ab = log a+log b
log<sub>a</sub>a = 1, and
log<sub>a</sub> sqrt(b)=(1/2)log<sub>a</sub> b
log 8
= log<sub>4</sub>4*2
=log<sub>4</sub>4+log<sub>4</sub>2
=1+log<sub>4</sub>2
=1+(1/2)log<sub>4</sub>4
=1+(1/2)(1)
=3/2
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