Asked by esmat
the second derivative of (sqrt((2x^3)+(6x)+(8)))
Answers
Answered by
Steve
y = sqrt(2x^3 + 6x + 8)
= (2x^3 + 6x + 8)^(1/2)
y' = 1/2 (2x^3 + 6x + 8)^(-1/2) * (6x + 6)
= (3x+3)/(2x^3 + 6x + 8)^(1/2)
= (2x^3 + 6x + 8)^(1/2)
y' = 1/2 (2x^3 + 6x + 8)^(-1/2) * (6x + 6)
= (3x+3)/(2x^3 + 6x + 8)^(1/2)
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