Ask a New Question
Search
Asked by
esmat
the second derivative of (sqrt((2x^3)+(6x)+(8)))
Answers
Answers
Answered by
Steve
y = sqrt(2x^3 + 6x + 8)
= (2x^3 + 6x + 8)^(1/2)
y' = 1/2 (2x^3 + 6x + 8)^(-1/2) * (6x + 6)
= (3x+3)/(2x^3 + 6x + 8)^(1/2)
Related Questions
Related
derivative of f(x) = x/(sqrt(x^2-4))
Find the derivative of cos(sqrt(e^(x^3)cos(x)) I got -sin(sqrt(e^(x^3)cos(x))*((sqrt(e^(x^3)cos(x...
find the derivative of y=sqrt of arctan x
derivative of ((Sqrt(x+3y)+sqrt(3xy))=(sqrt(21)+sqrt(90)) at point (6,5)google
Find the derivative. {sqrt(x+8)}*(x^2+20x) (x+8)^1/2(2x+20) minus (1/2)(x+8)^-1/2(x^2+20x) I'...
find the derivative of ln(sqrt((1-ln(x))/(1+ln(x)))
First derivative of sqrt(2(3^x)) × log(2x+5)
The derivative of f(x)=1/sqrt(2x-3), with x>3/2 is
what is the derivative of sqrt(2-3x)?
Find the derivative of sqrt(2x^2+1)