Asked by Tim
                find the derivative of ln(sqrt((1-ln(x))/(1+ln(x)))
            
            
        Answers
                    Answered by
            oobleck
            
    It looks messy, but you have
y = ln(sqrt((1-ln(x)) - ln(1+ln(x)))
= 1/2[ ln(1-lnx) - ln(1+lnx) ]
Now, using the chain rule, that is
y' = 1/2 [ 1/(1-lnx)*(-1/x) - 1/(1+lnx)*(1/x) ]
= 1/2 * 1/(x(lnx-1)(lnx+1))
    
y = ln(sqrt((1-ln(x)) - ln(1+ln(x)))
= 1/2[ ln(1-lnx) - ln(1+lnx) ]
Now, using the chain rule, that is
y' = 1/2 [ 1/(1-lnx)*(-1/x) - 1/(1+lnx)*(1/x) ]
= 1/2 * 1/(x(lnx-1)(lnx+1))
                    Answered by
            Bosnian
            
    In google paste:
math10 derivative calculator
Whe you see list of results click on:
Free Step-by-Step First Derivative Calculator(Solver) - Math10
When page be open in rectangle Function paste:
ln(sqrt((1-ln(x))/(1+ln(x))))
and click option:
Find derivative
You will see solution step-by-step.
    
math10 derivative calculator
Whe you see list of results click on:
Free Step-by-Step First Derivative Calculator(Solver) - Math10
When page be open in rectangle Function paste:
ln(sqrt((1-ln(x))/(1+ln(x))))
and click option:
Find derivative
You will see solution step-by-step.
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