Ask a New Question

Question

(2x+1)^2 +4=0

solve the equation. help please :(
13 years ago

Answers

Reiny
(2x+1)^2 = -4

Something squared cannot be negative.
There is no solution to your equation in the set of real numbers
If you accept complex roots ....
2x+1 = ± √-4 = ± 2i
2x = -1 ± 2i
x = (-1 ± 2i)/2
13 years ago

Related Questions

if a=6 and b=-4, solve the equation (4a+4b) (4a-b) solve exactly for a in the equation: log a^5 + log a^(3/2) = log 625 4 2... Can you help me solve this equation. 6n-(-2n)+8 How to set up to solve the equation 2 KCLO^3 ---> 2KCL + 3O^2 HOW MANY MOLES OF O^2 CAN BE PRODUCED... how to solve the following equations giving your answer correct to 2 decimal places where necessary... Solve the following set of equations. Can I use y = mx + b to calculate the equation 4x−y = 6... Please solve the following equation AND show all of your work. 21.3 = x + 5.1 Solve for x 𝑥 in the equation 102.5(x−11.92)=71.6 102.5 ( 𝑥 − 11.92 ).. Solve for n 𝑛 in the equation 50.3(n+9.25)=−120.72 50.3 ( 𝑛 + 9.25 ) = − 120.72 .(1 poi... Solve for x 𝑥 in the equation 811(x+45)=2455 8 11 ( 𝑥 + 4 5 ) = 24 55 .(1 point)..
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use