Question

Please Help

Solve each equation for 0<x<2 pi

2cos^ 2 x +sins-1=0

Answer 1

Please proof read.

Answer 2

Solve equation for 0< Equality x < 2pi

Trig equations

Answer 3

I'm not sure if this is right but this is what I have so far

2cos^2 +sinx -1 =0
2cos ^2 x+sinx =1 (I added 1 to both sides)
Cos^2 x +sinx

Answer 4

you have to keep writing an equation; you just dropped off the right side. In any case, remember from your Algebra I that you usually need to set stuff to zero to solve.

Now, using the fact that sin^2x+cos^2x=1,

2cos^2x+sinx-1 = 0
2-2sin^2x + sinx-1 = 0
2sin^2x-sinx-1 = 0
(2sinx+1)(sinx-1) = 0
sinx = -1/2 or 1

Now list the angles in all the quadrants that fit.