Asked by don
Solve cosxtanx + sqroot3cosx - sqroot3/2tanx - 3/2 = 0
interval 0 to 2 pi
exact answers and formula for the general solution as well as the specific solutions.
Sorry Steve, missed it last night.
interval 0 to 2 pi
exact answers and formula for the general solution as well as the specific solutions.
Sorry Steve, missed it last night.
Answers
Answered by
Steve
If I'm reading it right, we have
cos tan + √3 cos - √3/2 tan - 3/2 = 0
rearrange terms a bit to get
tan(cos - √3/2) + √3(cos - √3/2) = 0
(tan + √3)(cos - √3/2) = 0
tan x = -√3 --> x = 2pi/3 or 4pi/3
x = (2k+1)*pi +/- pi/3
cos x = √3/2 --> x = pi/6 or 11pi/6
x = k*2pi +/- pi/6
cos tan + √3 cos - √3/2 tan - 3/2 = 0
rearrange terms a bit to get
tan(cos - √3/2) + √3(cos - √3/2) = 0
(tan + √3)(cos - √3/2) = 0
tan x = -√3 --> x = 2pi/3 or 4pi/3
x = (2k+1)*pi +/- pi/3
cos x = √3/2 --> x = pi/6 or 11pi/6
x = k*2pi +/- pi/6
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