Asked by lilpump

cosxtanx-sin^2x=0

solve for x over the domain
0 is less than or equal to x which is less than or equal to 2pi

8 years ago

Answered by Scott

sin(x) - sin^2(x) = 0

sin(x) [1 - sin(x)] = 0

sin(x) = 0

sin(x) = 1

8 years ago

Answered by lilpump

x= pi, 0, 2pi, and pi/2 ?

8 years ago

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