Asked by Megan
Two hoses are connected to a swimming pool. Working together, they can fill the pool in 4 hr. The larger hose, working alone, can fill the pool in 6 hr less time than the smaller one. How long would it take the smaller one, woking alone, to fill the pool?
Please explain
Please explain
Answers
Answered by
Steve
If small = s, big = b, sb = both, then
1/sb = 1/s + 1/b
1/4 = 1/s + 1/6
1/12 = 1/s
s = 12 hours
1/sb = 1/s + 1/b
1/4 = 1/s + 1/6
1/12 = 1/s
s = 12 hours
Answered by
Megan
Thank you!
Answered by
Steve
Yeah. Too bad I did it wrong. I read "6 hours" rather than "6 hours less".
It's been done correctly later on.
It's been done correctly later on.
Answered by
Steve
See the solution to the problem posted Nov 5 at 10:18 pm