How many moles Cl^- do you want? That is M x L = 0.2M x 0.070 L = 0.014 moles.
Since there are 3 Cl atoms in 1 molecule of AlCl3, you will need 1/3 of that in moles AlCl3. 0.014/3 = 0.00467 moles AlCl3.
moles AlCl3 = M AlCl3 x L AlCl3. You know moles and you know M (1.5M), solve for L and convert to mL. I get an answer of about 3 mL but that isn't exact.
How many milliliters of a 110mL solution of 1.5 M AlCl3 must be used to make 70mL of a solution that has a concentration of 0.2M Cl–?
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