Asked by Monique
a 10.0mL sample of an unknown H3PO4 solution requirs 112mL of 0.100 M KOH to completely react with the H3PO4. What was the concentrartion of the unknown H3PO4 solution?
H3PO4 + 3KOH -----> 3H2O + K3PO4
Ive seen these problems with one volume but not two volumes Im lost please help me with this problem
H3PO4 + 3KOH -----> 3H2O + K3PO4
Ive seen these problems with one volume but not two volumes Im lost please help me with this problem
Answers
Answered by
DrBob222
That's not a big complication.
moles KOH = M x L = ?
Convert moles KOH to moles H3PO4 with the coefficients in the balanced equation.
M H3PO4 = moles H3PO4/L H3PO4.
done.
moles KOH = M x L = ?
Convert moles KOH to moles H3PO4 with the coefficients in the balanced equation.
M H3PO4 = moles H3PO4/L H3PO4.
done.
Answered by
Monique
DrBob222 I think Im doing something wrong. When I worked this problem out I came up with the right answer but wrong units.
0.112L KOH x 0.100molKOH/LKOH x 1mol H3PO4/3 mol KOH x 0.01 L H3PO4/1 mol H3PO4 = 0.373 L H3PO4
0.112L KOH x 0.100molKOH/LKOH x 1mol H3PO4/3 mol KOH x 0.01 L H3PO4/1 mol H3PO4 = 0.373 L H3PO4
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