Question

The following four forces act on 4.00 kg object:
F1 = 300 N east
F2 = 700 N north
F3 = 500 N west
F4 = 600 N south
What is the acceleration of the object?

Answer 1

resultant N: 100N
reslultantW: 200W

resulatant: sqrt50000 in the direction arctan 2 N of W

acceleration=that force/4kg

Answer 2

F3-F1
500-300
200N west

F2-F4
700-600
100N north


100N north and 200N west
100^2+200^2=c^2
10000+40000=c^2
50000=c^2
√50000=c
100√5=c
223.6N

tanx=200/100
tanx=2
x=arctan(2)
x=63.4 degrees

223.6N, 63.4 degrees west of north.

f=ma
223.6/4=a
55.9m/s^2=a

55.9m/s^2 63.4 degrees west of north.

Answer 3

1+1?

Answer 4

55.9 m/s2 in a direction 26.6∘ north of west.