Asked by gian

Two forces of 3N and 2N are acting at an angle of 45 to each other. Find the magnitude and direction of the resultant force?

Answers

Answered by Damon
3 in x direction

2 /sqrt 2 in x and 2/sqrt2 in y

x force = 3 + 2/sqrt2
y force = 2/sqrt 2

}F} = sqrt [ (3 + 2/sqrt2)^2 + 9 ]

tan angle above x axis = [ (2/sqt2)/(3 +2/sqrt2)]
Answered by Reiny
or

complete the parallelogram
r^2 = 3^2 + 2^2 - 2(3)(2)cos135°
= 13 - 12(-1/√2)
r = appr 4.6 N

or

direction vector = (3,0) + (2cos45, 2sin45)
= (3,0) + (1.414, 1.414) = (4.414 , 1.414)
magnitude = √(4.414^2 + 1.414^2) = appr 4.6

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