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Asked by Lee

The position function of a particle is given by s=t^3-3t^2-6t, t > =0.

when does the particle reach a velocity of 66 m/s?
14 years ago

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Answered by Steve
just plug and chug:

66 = 3t^2 - 6t - 6

solve for t
14 years ago
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The position function of a particle is given by s=t^3-3t^2-6t, t > =0.

when does the particle reach a velocity of 66 m/s?

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