Asked by Lee
The position function of a particle is given by s=t^3-3t^2-6t, t > =0.
when does the particle reach a velocity of 66 m/s?
when does the particle reach a velocity of 66 m/s?
Answers
Answered by
Steve
just plug and chug:
66 = 3t^2 - 6t - 6
solve for t
66 = 3t^2 - 6t - 6
solve for t
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