Ask a New Question

Question

position function is x(t)=(t-1)^3 (2t-3)

how do you find the velocity of the particle at nay time when t is greater or equal to 0?

i got the derivative equation (6t-9)(t-1)^2 + 2(t-1)^3
but that is for all t.
16 years ago

Answers

drwls
Your formula is correct. All you have to do is apply if for positive t only.
16 years ago

Related Questions

Use the position function s(t)=-4.9t^2+ 150, which gives the height (in meters) of an object that ha... Given the position function of an object moving in a straight line, measured in meters, from the ori... A position function has the positions listed below. t 2 4 7 10 12 f(t) 34 98... Given the position function, s of t equals t cubed divided by 3 minus 12 times t squared divided by... The position function x(t) of a particle moving along an x axis is x = 6.00 - 8.00t2, with x in mete... Given the position function, s of t equals negative t cubed divided by 3 plus 13 times t squared div... For the position function r(t)= (2+t^2,3t), determine the approximate angle between the acceleration... Given the position function, s(t)= (-t^3/3)+(13t^2 /2)-30t, between t=0 and t = 9, where s is give... Given a position function for an object, under which of these conditions is the object’s speed decre...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use