Question

Given the position function s = 4t^3 − 24t^2 + 6t + 6.

find s and v when a = 0

(Where v is the velocity and a is the acceleration.).

Answer 1

v= ds/dt=12t^2-48t+6
a= dv/dt=24t-48=0 so t=2

find s, v when t=2

Answer 2

so i just have to sub t=2 in
v = 12t^2-48t+6 to get v and
s = 4t^3-24t^2+6t+6 to get s ?