It is given a quadratic function y=a(x-h)62+k.If its graph is a parabola with x=2 as its axis of symmetry,and it passes through the two points(3,7)and(4,11)

Question

(a)what isthe value of the constant h?
(b)find the values of the constants a and k,and write down the quadratic function.

Answer 1

If its axis of symmetry is x=2, then h=2

7 = a + k
11 = 4a + k

3a = 4
a = 4/3
k = 17/3

y = 4/3(x-2)^2 + 17/3